Program to illustrate the solution of fizz-buzz problem in C.

Code Box
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/* Program to print fizz in place of multiple of 3 and buzz in place of 5 */

#include<stdio.h>
#include<conio.h>
void main()
{
int i;

for(i=1;i<=50;i++)
{
if(i%(3*5)==0)
{
printf("BuzzFizz");
}
else if(i%5==0)
{
printf("Buzz");
}
else if(i%3==0)
{
printf("Fizz");
}
else
{
printf("%d",i);
}

if(i%10==0)
{
printf("\n");
}
else
{
printf("\t");
}

}

getch();
}