Code Box
----------------------------------------------
/* Program to Solve Quadratic Equation Using Conditional operator and Switch */
/* In quadratic equation we need values of a,b,c
and D=(b square -4.a.c)
and every thing depends on the value of D
*If D grater than 0 multiple and real root
*If D==0 only single root
*If D is less than 0 than imaginary roots
*/
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int a,b,c,D,n;
float x1,x2,D1;
clrscr();
printf("\nEnter Values");
printf("\n a = ");
scanf("%d",&a);
printf("\n b = ");
scanf("%d",&b);
printf("\n c = ");
scanf("%d",&c);
printf("\nEnterd Values are : a=%d b=%d c=%d",a,b,c);
printf("\nQuadratic Equation Calculation:");
D=(b*b)-(4*a*c);
printf("\nValue of Normal D= %d ",D);
D1=abs(D);
D1=sqrt(D1);
printf("\nValue of Squared D= %.3f ",D1);
n=(D>=0)?(D==0?2:1):3;
printf("\nValue of n : %d",n);
switch(n)
{
case 1:
//Multiple Roots
printf("\nReal & Multiple Roots");
x1=((b+D1)/(2*a));
x2=((b-D1)/(2*a));
printf("\n\nRoots are X1=%.3f X2=%.3f ",x1,x2);
break;
case 2:
//Single Root
printf("\nReal & Single Roots");
x1=((b)/(2*a));
printf("\n\nRoots are X1=%.3f",x1);
break;
case 3:
//Imaginary Part
printf("\nImaginary Roots");
printf("\nX1=(%d+%.3fi)/2*%d",b,D1,a);
printf("\nX2=(%d-%.3fi)/2*%d",b,D1,a);
break;
default:
printf("\nWrong Entry, Error!!!");
}
getch();
}
